Answer:
0.003060 cm³
Step-by-step explanation:
Mass of water = m = 326.75 gram
Density of water = ρ = 1.00 g/mL = 1 g/cm³
density = mass / volume
⇒volume = density / mass
⇒volume = 1 / 326.75
⇒Volume = 0.0030604 cm³
∴ Volume held by beaker = 0.0030604 cm³
Here the combined mass of the beaker and water is given so the volume found will be of the beaker as well as the liquid. But, it can be seen that the volume is so small that subtracting the beaker mass would have negligible effect.