221k views
4 votes
What is the minimum uncertainty in the energy state of an atom if an electron remains in this state for 10 s

User Stuckless
by
5.9k points

2 Answers

0 votes

Final answer:

The minimum uncertainty in the energy state of an atom can be found using the Heisenberg Uncertainty Principle. If an electron remains in a state for 10 seconds, the minimum uncertainty in its energy is approximately 5.3x10^-25 J. The uncertainty principle states that there is a fundamental limit to how precisely we can simultaneously know certain pairs of physical properties, such as energy and time.

Step-by-step explanation:

The minimum uncertainty in the energy state of an atom can be found using the Heisenberg Uncertainty Principle. The uncertainty in energy (AE) is given by the equation AEAt ≥ h/4π, where At is the uncertainty in time and h is Planck's constant. In this case, if the electron remains in the state for 10 s (At = 10 s), the minimum uncertainty in the energy can be calculated. Substituting the known values into the equation, we find the minimum uncertainty in energy to be approximately 5.3x10-25 J.

The uncertainty principle states that there is a fundamental limit to how precisely we can simultaneously know certain pairs of physical properties, such as energy and time. The uncertainty in energy is inversely proportional to the uncertainty in time. Therefore, the longer the electron remains in the energy state, the smaller the uncertainty in energy will be. This means that the more stable the state, the more accurately we can determine its energy value.

It is important to note that the uncertainty in energy is relatively small compared to typical excitation energies in atoms, which are on the order of 1 eV. Therefore, the uncertainty principle has a minimal effect on the accuracy with which we can measure the energy of such states.

User Riley Major
by
5.5k points
4 votes

Answer:

The minimum uncertainty in the energy state of an atom is
1.0557*10^(-35)\ J

Step-by-step explanation:

Given that,

Time t = 10 s

We need to calculate the minimum uncertainty in the energy state

Using Hisen burg of uncertainty principle equation


\Delta E\Delta t=(h)/(2\pi)


\Delta E=(h)/(2\pi)*(1)/(\Delta t)

Where, E = energy

t = time

Put the value into the formula


\Delta E=(6.63*10^(-34))/(2*3.14)*(1)/(10)


\Delta E=1.0557*10^(-35)\ J

Hence, The minimum uncertainty in the energy state of an atom is
1.0557*10^(-35)\ J

User Stephan Dollberg
by
5.3k points