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Find the x-intercepts (if any) for the graph of the quadratic function below. 6 y+4=(x-2)^2 a) (0, 0) and (-4, 0) b) (0, 0) and (4, 0) c) (0, 0) d) (-4, 0) and (4, 0) e) none

User Brary
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1 Answer

4 votes

Answer:

The function has two x-intercepts at (0,0) and (4,0).

Explanation:

Consider the provided function.


y+4=(x-2)^2

The x-intercepts are the point, where y is 0.

To find x-intercepts, substitute y = 0 in the provided equation and solve for x.


0+4=(x-2)^2


4=(x-2)^2


\pm√(4)=x-2


\pm2=x-2


2=x-2 or
-2=x-2


2+2=x or
-2+2=x


4=x or
0=x

Therefore, the function has two x-intercepts at (0,0) and (4,0).

User Chella
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