Question

The gear motor can develop to 1/2 hp when it turns at 300 rev/min. If the shaft has a diameter of 1/2 in. determine the maximum shear stress in the shaft

Answer 1

145.902 psi

Step-by-step explanation: Given power = 0.5 hp= 225 ft-lb/sec, N= 300 rpm shaft

dia= 0.5 inch

We know that power transmitted by circular shaft is

`P=(2piNT)/(60)`

now putting the values to find torque

⇒
`T=(60P)/(2piN)`
`=(60*225)/(2* pi*300)`

⇒T=7.16 lb-ft

now to calculate shear stress
`\tau=(16T)/(pi*d^(3) )`

⇒
`\tau =(16*7.16)/(pi*0.5^3)`

⇒
`\tau`=145.902 psi

hence maximum shear stress in the shaft is 145.902 psi