Question

A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located at the center of the sphere and point B is 15 cm from the center, what is the magnitude of the electric potential difference between these two points?

Answer 1

`\Delta V = 30V`

Step-by-step explanation:

give data:

inside diameter = 5.0 cm

charge q = 0.25 nC

Outside diameter = 15 cm

potential V at inside sphere is =
`V=(kq)/(R)`

potential V at outside sphere is =
`V=(kq)/(r)`

k is constant whose value is =
`8.99 *10^(9)Nm^(2)/c^2`

then potential difference between two point is

`\Delta V = kq \left [(1)/(R)-(1)/(r)  \right ]`

`\Delta V = 9*10^(9)*0.25*10^(-9) \left [(1)/(0.05)-(1)/(0.15) \right ]`

`\Delta V = 30V`