Question

Question number 8 please please fast

Answer 1

`a_n=-(1)/(n)`

`a_6=-(1)/(6)` is our sixth term.

`a_7=-(1)/(7)` is our seventh term.

`a_8=-(1)/(8)` is our eighth term.

Explanation:

So every number in this sequence is -.

If you write 1 as 1/1, then you should see the numerator is constant one while the denominator is going up by 1 each time.

So the patter is

`a_n=-(1)/(n)`

Test if you like:

n=1 gives us
`a_1=-(1)/(1)=-1` which is our first term.

n=2 gives us
`a_2=-(1)/(2)` which is our second term.

n=3 gives us
`a_3=-(1)/(3)` which is our third term.

n=4 gives us
`a_4=-(1)/(4)` which is our fourth term.

n=5 gives us
`a_5=-(1)/(5)` which is our fifth term.

Now we are going to use
`a_n=-(1)/(n)`

to write our next three terms:

n=6 gives us
`a_6=-(1)/(6)` which is our sixth term.

n=7 gives us
`a_7=-(1)/(7)` which is our seventh term.

n=8 gives us
`a_8=-(1)/(8)` which is our eighth term.