Question

(x - 4)2 + (y + 6)2 = 52

what are the length of the radius and the coordinates of the center for this particular circle? Watch your signs for the variables h and k.

Answer 1

(x − 4)2 + (y + 6)2 = 25

(x − 4)2 + (y − (-6))2 = 52

When I compare my equation with the standard form, (x − h)2 + (y − k)2 = r2, I get h = 4, k = -6, and r = 5. The center is at (4, -6), and the length of the radius is 5.

Explanation:

Plato :)

Answer 2

Radius r = ±√52

Coordinates of center =

Explanation:

Points to remember

Equation of a circle passing through the point (x1, y1) and radius r is given by

(x - x1)² + (y - y1)² = r ²

To find the radius and coordinates of center

It is given that an equation of circle,

(x - 4)² + (y + 6)² = 52

Compare two equations,

we get r ² = 52

r = ±√52

(x - x1)² = (x - 4)² then x1 = 4

(y - y1)² = (y + 6)² then y1 = -6

Coordinates of center = (4, -6)