Answer:
$280.51
Explanation:
The formula we want to use:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/44vs2zpmywawbh2b7k4ss2gheb6z49ybcd.png)
where:
P is the principal
r is the the rate
n is the number of compounding per year
t is total number of years
A is the ending amount
We are given P=200, r=.07, n=1 (compounded once a year), t=5.
So plugging this in:
![A=200(1+(.07)/(1))^(1 \cdot 5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cfse0aqrfybek7oa7cv7yydbs8d0vm5u9u.png)
Simplify a little:
![A=200(1+.07)^(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qlzkjkykyvd9ub13llr1cbtf3rljq105bq.png)
Just a little more:
![A=200(1.07)^(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i7s4vj5jpxt1urya9lcfakd7oaqgmy4hk8.png)
Now I'm going to put the rest of this in the calculator:
200*(1.07)^5 is what I'm putting in my calculator.
This is approximately 280.5103461.
To the nearest cent this is 280.51