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How is ( a || b ) && c || ( a || b ) && ( ! c ) equal to ( a || b ) without simplification?

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Answer: You can see the truth table in the image.

Explanation:We can do this question by using truth table.

As we can see in the truth table that there is no effect on the output of the expression by c if a and b both are false then the output is false and if any of them is True or both of them are True then the result is True.

How is ( a || b ) && c || ( a || b ) && ( ! c ) equal to ( a || b-example-1
How is ( a || b ) && c || ( a || b ) && ( ! c ) equal to ( a || b-example-2
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