Question

Convert the value 43.28 lbf/in3 to standard SI units

Answer 1

`43.28(lbf)/(in^3)=43.28* 27460.68(kg)/(m^3)=1188498.44(kg)/(m^3)`

Step-by-step explanation:

Here the given values corresponds to the density of a substance

The density of a substance in standard SI unit is given as Kg/m³.

Given value = 43.28lbf/in³

also

we know,

1 lbf = 0.45kg

1in = 0.0254 m

thus,

`(1lbf)/(1in^3)=(0.45kg)/(0.0254^3m^3)=27460.68(kg)/(m^3)`

therefore,

`43.28(lbf)/(in^3)=43.28* 27460.68(kg)/(m^3)=1188498.44(kg)/(m^3)`