Question

A girl with a mass of 40 kg is swinging from a rope with a length of 3.3 m. What is the frequency of her swinging?

Answer 1

Frequency, f = 0.274 Hz

Step-by-step explanation:

It is given that,

Mass of the girl, m = 40 kg

Length of the rope, L = 3.3 m

We need to find the frequency of her swinging. It is an example of simple harmonic motion whose time period is given by :

`T=2\pi\sqrt{(L)/(g)}`

`T=2\pi\sqrt{(3.3\ m)/(9.8\ m/s^2)}`

T = 3.64 seconds

The frequency,
`f=(1)/(T)`

`f=(1)/(3.64\ s)`

f = 0.274 Hz

So, the frequency of her swinging is 0.274 Hz. Hence, this is the required solution.