Question

A 3.0 kg ball tied to the end of a 50 cm long string being swung in a circle in a horizontal plane at constant speed. If the tension of the string is 3.8 N, what is the speed of the ball?

Question 31 options:

A)

1.2 m/s
B)

1.0 m/s
C)

1.4 m/s
D)

0.8 m/s

Answer 1

The speed of the ball is 0.8 m/s.

(D) is correct option.

Step-by-step explanation:

Given that,

mass of ball = 3.0 kg

length = 50 cm

We need to calculate the speed of the ball

Using relation between the centripetal force and tension

`(mv^2)/(r)=T`

`v^2=(T* r)/(m)`

Where, m = mass

T = tension

r = radius

Put the value into the formula

`v=\sqrt{(3.8*50*10^(-2))/(3.0)}`

`v=0.8\ m/s`

Hence, The speed of the ball is 0.8 m/s.