Question

A force of 7.50N is applied to a spring whose spring constant is 0.289 N/cm. Find its change in length.​

Answer 1

Hook's law states that

`F=k\Delta x`

where F is the applied force, k is the spring constant, and
`\Delta x` is the change in length.

Plugging your values, we have

`7.5 = 0.289\Delta x \implies \Delta x = (7.5)/(0.289)\approx 25.95`