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A given line has the equation .

2X - 12Y = -1
What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

A. Y = -6X + 9
B. Y = - 1/6X + 9
C. Y = 1/6X +9
D. 6X+ 9

User Kiliandeca
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1 Answer

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Answer:

A. Y = -6X + 9

Explanation:

Solving for y, we can find the slope of the given line. It is the coefficient of x, 1/6.

-12y = -2x -1

y = 1/6x +1/12

The perpendicular line will have a slope that is the negative reciprocal of this:

m = -1/(1/6) = -6

The y-intercept will be the y-value corresponding to x=0. That value is b=9, given to us by the point the line is to go through. So, we have the slope-intercept form ...

y = mx + b

y = -6x + 9

A given line has the equation . 2X - 12Y = -1 What is the equation, in slope-intercept-example-1
User Manabu Tokunaga
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