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The height of the parallelogram, h, can be found by dividing the area by the length of the base. If the area of the parallelogram is represented by 4x2 – 2x + 5 and the base is 2x – 6, which represents the height? 2x + 5 + 2x – 7 – 2x – 7 + 2x + 5 –

2 Answers

6 votes

Answer:


2x+5+(35)/(2x-6)

Explanation:

Given,

The area of the parallelogram, A =
4x^2-2x+5

The length of its base, b =
2x-6

∵ The height of the parallelogram.


h=(A)/(b)


\implies h=(4x^2-2x+5)/(2x-6)


=2x+5+(35)/(2x-6) ( by long division shown below )

Hence, the height of the given parallelogram is,


2x+5+(35)/(2x-6)

The height of the parallelogram, h, can be found by dividing the area by the length-example-1
User Chrisdot
by
7.9k points
3 votes

Answer:


(4x^(2)-2x+5)/(2x-6) =2x + 5 + (35)/(2x-6)

Explanation:

We know that the height of a parallelogram can be found by divind the area by the lenght of the base.

The area is 4x2 – 2x + 5 and the base is 2x – 6. To find the height, we need to divide both polynomials:


(4x^(2)-2x+5)/(2x-6) =2x + 5 + (35)/(2x-6)

User Croote
by
7.7k points