Answer:
The last scoring rule makes a fair game
If card value is less than 3, Player 1 earns 3 points. If not, Player 2 earns 2 points.
Explanation:
This is a question which relates to probabilities, complementary probabilities and expected outcomes
Since there are 5 cards in total and only 1 card is picked, the probability of picking a card is the same i.e. 1/5 = 0.2 since each card is identical and therefore has the same likelihood of being drawn
Let's go through each of the rules, find the associated outcomes and probabilities of each of the outcome
The attached table shows a summary of all the possible outcomes of each rule, the probabilities associated with it, the complement of the rule, the complement probability, expected payoffs and who has the advantage for each rule
As an example, take the first row relating to the first rule:
If value of card is greater than 2, Player 1 earns 2 points. If not, Player 2 earns 2 points.
If the value is greater than 2 then the value is either {3, 4 or 5}. There are 3 possible outcomes out of a total of 5 so,
P(card value > 2) = P(3, 4, 5) = 3/5 = 0.6 and Player 1 gets 2 points so the expected value = 0.6 x 2 = 1.2 EP(P1
The complement of this event is
card value <=2 ie card value is either 1 or 2 ie 2 possible out of 5
P(card value <=2) = P(1,2) = 2/5 = 0.4
Note that this probability is 1 - P(card value > 2) = 1- 0.6 = 0.4
If so, Player 2 gets 2 points and his/her expected payoff is 0.4 x 2 = 0.8 EP(P2)
Since EP(P1) > EP(P2) this rule gives player 1 an advantage and therefore not a fair game
The other rows of the table can be interpreted the same way. Essentially we are looking for a rule that gives both players the same expected payoff and therefore each player has the same chance of winning
The table shows that the last rule is the fairest