Question

What is the equation of the following line written in general form? (the y-intercept is -1) (1,1)

Answer 1

`\bf \stackrel{\textit{y-intercept}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{-1})}\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-1)}{1-0}\implies \cfrac{1+1}{1}\implies \cfrac{2}{1}\implies 2 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-1)=2(x-0) \\\\\\ y+1=2x\implies \stackrel{\textit{general form}}{-2x+y+1=0}`