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If h(x)=4X^2-16 were shifted 5units to the right and 2 down, what would the new equation be

User Maruful
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2 Answers

1 vote

Answer:

4(x - 5)^2 - 18.

Explanation:

For a move 5 to the right f(x) ----> f(x - 5).

For a move of 2 down f(x - 5) ----> f(x - 5) - 2.

User Hao Wu
by
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1 vote

For this case we have that by definition of function transformation is fulfilled:

Let h> 0:

To graph
y = f (x-h), the graph moves h units to the right.

To graph
y = f (x + h), the graph moves h units to the left.

Let k> 0:

To graph
y = f (x) + k, the graph k units is moved up.

To graph
y = f (x) -k, the graph moves k units down.

So, we have the following function:


h (x) = 4x ^ 2-16

5 units on the right:


h (x) = 4 (x-5) ^ 2-16

2 units down


h (x) = 4 (x-5) ^ 2-16-2\\h (x) = 4 (x-5) ^ 2-18

Answer:


h (x) = 4 (x-5) ^ 2-18

User Dexametason
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