Question

A given line has the equation 10x - 2y=-2.

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?
y= -5x+12
5x+y=12
y- 12 = 5(x - 1)
5x+y=-1

Answer 1

y= -5x+12

Explanation:

slope int form ; y=mx+b

that is the only option in that form.

Answer 2

the equation is y = 5x + 12

Explanation:

The equation of line is 10x - 2y=-2

Write this equation in slope intercept form of line y = mx + b

`10x-2y=-2\\\\2y=10x+2\\\\y=5x+1`

Therefore, the slope of the line is m = 5

Now, we know that parallel lines have same slope.

Hence, slope of the required line is also 5.

Thus, the equation of line is in the form y = 5x + b

Now, use the point (0,12) to find b

12= 5(0) + b

b = 12

Hence, the equation is y = 5x + 12