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Membrane walls of living cells have surprisingly large electric fields across them due to separation of ions. What is the voltage across an 8.47-nm-thick membrane if the electric field strength across it is 8.76 MV/m? You may assume a uniform E-field.

User Emelyn
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1 Answer

3 votes

Answer:

Voltage, V = 0.0741 volts

Step-by-step explanation:

It is given that,

Width of membrane,
d=8.47\ nm=8.47* 10^(-9)\ m

Electric field strength,
E=8.76\ MV/m=8.76* 10^6\ V/m

We need to find the voltage across membrane. Electric field is given by :


E=(V)/(d)


V=E* d


V=8.76* 10^6\ V/m* 8.47* 10^(-9)\ m

V = 0.0741 V

So, the voltage across the membrane is 0.0741 volts. Hence, this is the required solution.

User Tuan Dao
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