Question

An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of "2.7" non-work-related e-mails per hour. Assume the arrival of these e-mails is approximated by the Poisson distribution. a. What is the probability Linda Lahey, company president, received exactly 3 non-work-related e-mails between 4 P.M. and 5 P.M. yesterday

Answer 1

Answer: 0.2205

Explanation:

Given : Technology Services department at Lahey Electronics revealed company employees receive an average of "2.7" non-work-related e-mails per hour.

i.e.
`\lambda = 2.7`

If the arrival of these e-mails is approximated by the Poisson distribution.

Then , the required probability is given by :-

`P(X=x)=(\lambda^xe^(-\lambda))/(x!)\\\\P(X=3)=((2.7)^3e^(-2.7))/(3!)\\\\=0.22046768454\approx0.2205`

Hence, the probability Linda Lahey, company president, received exactly 3 non-work-related e-mails between 4 P.M. and 5 P.M. yesterday =0.2205