Answer:
* The values of x are 0 and 4
Explanation:
* Lets explain how to solve the problem
- f(x) = x² - 2x - 4 is a quadratic function
- g(x) = 2x - 4
∵ f(x) and g(x) are intersected
∴ They meet each other in a point
- To find this point equate the two functions
∵ f(x) = g(x)
∵ f(x) = x² - 2x - 4
∵ g(x) = 2x - 4
∴ x² - 2x - 4 = 2x - 4 ⇒ subtract 2x from both sides
∴ x² - 4x - 4 = -4
- Add 4 to both sides
∴ x² - 4x = 0
- Take x as a common factor
∴ x(x - 4) = 0
- Equate each factor by 0
∴ x = 0
- OR
∴ x - 4 = 0 ⇒ add 4 to both sides
∴ x = 4
∴ f(x) and g(x) intersected at x = 0 and x = 4
* The values of x are 0 and 4