Question

Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electric field at a point between the two surfaces?

Answer 1

Electric field, E = 45.19 N/C

Step-by-step explanation:

It is given that,

Surface charge density of first surface,
`\sigma_1=0.2\ nC/m^2=0.2* 10^(-9)\ C/m^2`

Surface charge density of second surface,
`\sigma=-0.6\ nC/m^2=-0.6* 10^(-9)\ C/m^2`

The electric field at a point between the two surfaces is given by :

`E=(\sigma)/(2\epsilon_o)`

`E=(\sigma1-\sigma_2)/(2\epsilon_o)`

`E=(0.2* 10^(-9)-(-0.6* 10^(-9)))/(2* 8.85* 10^(-12))`

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.