Question

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.54 cm. (1 f-12 inches)

Answer 1

Answer: The density of gold in
`g/cm^3` is
`19.22g/cm^3`

Step-by-step explanation:

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

`\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}`

We are given:

Density of gold =
`1200lb/ft^3`

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into
`g/cm^3`, we get:

`\Rightarrow ((1200lb)/(ft^3))* ((453.6g)/(1lb))* ((1ft)/(12inch))^3* ((1inch)/(2.54cm))^3\\\\\Rightarrow 19.22g/cm^3`

Hence, the density of gold in
`g/cm^3` is
`19.22g/cm^3`