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In an experiment to determine the s.h.c. of lead, a 0.80 kg block of lead is heated using a

60 W electric heater for 5.0 minutes. Calculate the energy supplied by the heater in this
time.

User Dinu
by
2.9k points

2 Answers

10 votes
10 votes

Final answer:

To calculate the energy supplied by the heater, multiply the power of the heater (60 W) by the time the heater is on in seconds (300 s), resulting in 18,000 joules of energy supplied to the lead block.

Step-by-step explanation:

The subject of the question is Physics, and it relates to the high school level. The question asks about calculating the energy supplied by a heater to a block of lead in a specific heat capacity (s.h.c.) experiment.

To calculate the energy supplied by the heater, we use the formula:

E = P × t

Where:

  • E is the energy in joules (J),
  • P is the power of the heater in watts (W),
  • t is the time in seconds (s).

First, we need to convert the time from minutes to seconds. Since there are 60 seconds in a minute, 5.0 minutes is equivalent to 5.0 × 60 = 300 seconds.

Now, we apply the formula:

E = 60 W × 300 s = 18,000 J

So, the energy supplied by the heater to the lead block is 18,000 joules.

User JJAN
by
3.3k points
10 votes
10 votes

Answer:2.47

Explanation: did the math

User Albert
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2.5k points