18.9k views
4 votes
Inâ 2001, the population in a town was 11% more than it was in 2000. If the population was 25,570 in 2002 which was 10% more than 2001 find the population in 2000

write the number (Round to the nearest wholeâ number.)

User Hetzbh
by
5.6k points

1 Answer

1 vote

Answer: There was population of 22808 in 2000.

Explanation:

Since we have given that

Population was in 2002 = 25,570

According to question, the population in 2002 was 10% more than 2001.

So, the population in 2001 was


25570=P_1(1+(r)/(100))\\\\25570=P_1(1+(10)/(100))\\\\25570=P_1(1+0.1)\\\\25570=P_1(1.01)\\\\(25570)/(1.01)=P_1\\\\25316.8\approx 25317=P_1

Now, we have given that

In 2001, the population in a town was 11% more than it was in 2000.

So, population in 2000 was


25317=P_0(1+(r)/(100))\\\\25317=P_0(1+(11)/(100))\\\\\25317=P_0(1+0.11)\\\\25317=P_0(1.11)\\\\P_0=(25317)/(1.11)\\\\P_0=22808

Hence, there was population of 22808 in 2000.

User Hvtilborg
by
5.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.