Question

What are the zeros of the function below? Check all that apply.
F(x) =x(x-2)/(x+3)(x-5)

Answer 1

x = 0 and x = 2

Explanation:

`\text{The domain:}\\\\(x+3)(x-5)\\eq0\iff x+3\\eq0\ \wedge\ x-5\\eq0\\\\x\\eq-3\ \wedge\ x\\eq5\\\\========================\\\\f(x)=(x(x-2))/((x+3)(x-5))\\\\\text{The zeros are for}\ f(x)=0\\\\(x(x-2))/((x+3)(x-5))=0\iff x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\x=0\in D\ \vee\ x=2\in D`