Question

A Carnot heat engine has an efficiency of 0.200. If it operates between a deep lake with a constant temperature of 293.0 K and a hot reservoir, what is the temperature of the hot reservoir? O 352 K O 1760 K O 366 K 1470 K

Answer 1

366 K

Step-by-step explanation:

T₀ = Constant Temperature of deep lake = 293.0 K

T = Temperature of hot reservoir connected to carnot engine = ?

η = Efficiency of Carnot engine during the operation

Efficiency of Carnot engine is given as

`\eta = 1-(T_(o))/(T)`

Inserting the values

`0.200 = 1-(293.0)/(T)`

T = 366 K