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What is the distance between the polnts (3, 2) and (15, 16) on a coordinate plane?

What is the distance between the polnts (3, 2) and (15, 16) on a coordinate plane-example-1
User Kingwei
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1 Answer

4 votes

Answer:

C. 15 units

Explanation:

The formula of a distance between two points:


d=√((x_2-x_1)^2+(y_2-y_1)^2)

We have the points (3, 7) and (15, 16). Substitute:


d=√((15-3)^2+(16-7)^2)=√(12^2+9^2)=√(144+81)=√(225)=15

User Angel F Syrus
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