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The Ransin Sports Company has noted that the size of individual customer orders is normally distributed with a mean of $112 and a standard deviation of $9. If a soccer team of 11 players were to make the next batch of orders, what would be the standard error of the mean? 1.64 0.82 2.71 3.67

User NoelProf
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Answer: 2.71

Explanation:

We know that the formula to calculate the standard error is given by :-


S.E.=(\sigma)/(√(n)), where
\sigma is the standard deviation and 'n' is the sample size.

Given : Standard deviation :
\sigma=\$9

Sample size :
n=11

Then , the standard error of the mean is given by :-


S.E.=(9)/(√(11))=2.7136021012\approx2.71

Hence, the standard error of the mean = 2.71

User MJM
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