Question

Answer this question thanks:)

Answer 1

Look at the picture

Explanation:

`<,\ >-\text{op}\text{en circle}\\\\\leq,\ \geq-\text{closed circle}\\\\<,\ \leq-\text{draw a ray to the left}\\\\>,\ \geq-\text{draw a ray to the right}`

`(q)/(2)<2\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot(q)/(2\!\!\!\!\diagup_1)<2\cdot2\\\\q<4`

`\text{op}\text{en circle on number 4}\\\\\text{draw a ray to the left}`

Answer 2

First multiply 2 to both sides to isolate q. Since 2 is being divided by q, multiplication (the opposite of division) will cancel 2 out (in this case it will make 2 one) from the left side and bring it over to the right side.

`(q)/(2)` × 2 < 2 × 2

q < 4

For the graph will you have a empty or colored in circle?

If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.

If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.

Which direction will the ray go?

If the variable is LESS then the number then the arrow will go to the left of the circle.

If the variable is MORE then the number then the arrow will go to the right of the circle.

In this case your inequality is:

q < 4

aka q is less then four

This means that the graph will have an empty circle and the arrow will go to the left of 4. (look at image below)

Hope this helped!

~Just a girl in love with Shawn Mendes