Question

A satellite weighs 104 N at ground control. What best approximates the acceleration it experiences in orbit at an altitude of twice the earth's radius ifFpa = GME2thm, where r is the distance separating the centers of mass of the satellite and the Earth? O A. 111 m/s2 O B. 2.5 m/s O C. 1.1 m/s2 ○ D. 0 m/s

Answer 1

`a_c = 1.1 m/s^2`

Step-by-step explanation:

As we know that net force on the Satellite due to gravity will provide it centripetal force

so we can say here

`F_g = F_c`

`(GMm)/(r^2) = ma_c`

now we will have

acceleration given by the equation

`a_c = (GM)/(r^2)`

now we have

r = R + 2R = 3R

`a_c = (GM)/(9R^2)`

also we know that acceleration due to gravity on the surface of earth is given as

`g = (GM)/(R^2) = 9.8 m/s^2`

so the acceleration of satellite is given as

`a_c = (9.8)/(9) = 1.1 m/s^2`