Question 1

X(x-3)=x then the possible value of X are...

Question 2

$x(x-3)=x\\x^2-3x-x=0\\x^2-4x=0\\x(x-4)=0\\x=0\vee x=4$

Question 3

$\text{Hey there!}$

$\text{In order for you can do the distributive property then work from there}$

$\text{x(x - 4) = x}\\\\\text{x(x)=x}^2\\\\\text{x(-3)= -3x}$

$\text{Subtract by the value of x on your sides!}$

$\text{Your new equation becomes: x}^2\text{- 3x = x}$

$\text{Like}\downarrow$

$\text{x}^2\text{- 3x - x = x - x}$

$\text{x - x = 0 }$

$\text{-3x + (-1x) = -4x}$

$\text{Our equation becomes: x}^2\text{- 4x = 0}$

$\text{Next, we have to FACTOR on the LEFT side of your equation}$

$\text{x(x - 4) = 0}$

$\text{Set the numbers to FACTOR out to 0}$

$\text{Like: x = 0 or x - 4 = 0}\text{ (solve that and you SHOULD have the x-values)}$

$\boxed{\boxed{\bf{Answer: x = 0\ or \ x =4}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~
$\frak{LoveYourselfFirt:)}$

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