Answer:
Part a)
![22.95+0.43x \leq 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lfapz9r43awjfws0qaxecb5vdcg7hip347.png)
Part b) The maximum number of candy bars that you can purchase is 4
Part c) The change would be
![\$0.33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ucp8d3p19tmzk83jjfbp9kmb0az7siyepw.png)
Explanation:
Part a) Write an equation representing your shopping experience and use x for the number of candy bars
Let
x -----> the number of candy bars
we know that
The inequality that represent this problem is equal to
![2(3.50)+2(2.75)+10.45+0.43x \leq 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vb5w8bra6hncx06jp4k5rskm0muv3nxqf2.png)
![22.95+0.43x \leq 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lfapz9r43awjfws0qaxecb5vdcg7hip347.png)
Part b) Solve the equation to determine how many candy bars can you purchase?
![22.95+0.43x \leq 25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lfapz9r43awjfws0qaxecb5vdcg7hip347.png)
Solve for x
Subtract 22.95 both sides
![0.43x \leq 25-22.95](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3xvrdnv4gkvvadp4633a5km2g2x1an43gj.png)
![0.43x \leq 2.05](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aue02uey8zlcabjk13grgcszghmzv4j0nz.png)
Divide by 0.43 both sides
![x \leq 2.05/0.43](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rgdjf5dkcpa0gnctmfhiszfbnciwvw4nen.png)
![x \leq 4.8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mwiwtftn746jj15zpmv5d1yjgnym1oujmo.png)
The maximum number of candy bars that you can purchase is 4
Part c) How much change would you have left?
If you purchase 4 candy bars
then
![22.95+0.43(4)=\$24.67](https://img.qammunity.org/2020/formulas/mathematics/middle-school/23m7f6xmrxec4v7pudjta4o76530b25rt0.png)
therefore
![\$25-\$24.67=\$0.33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p9qr37cxxyawyyym1tiaqvog8wm9y6y8su.png)