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38 votes
38 votes
If a fox starts from rest and accelerates at a rate of 1.1 m/s2, how long does it take the fox to run 5 m

User Franki
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1 Answer

21 votes
21 votes

Answer:

3.02 seconds

Step-by-step explanation:

vf - vi = at

where vf and vi are the final and initial velocities, respectively. a is the acceleration and t is the time of acceleration. The units will be m/s for velocities, and ms^2 for acceleration.

The lazy fox has vi = 0

The final velocity, vf, is equal to at + vi, or simply "at" for our sleepy fox.

The average velocity would be at/2.

Distance travelled would be the average velocity times the time, or:

(vf/2)*t = distance

We want to know how long it will take to go 5 m, so set distance = 5 m:

(at/2)*t = distance

(at/2)*t = 5 m

((1.1m.s^2)t/2)*t = 5 m

((1.1m.s^2)t)*t = 10 m

t*t = (10m)/((1.1m.s^2)

t^2 = 9.09 s^2

t = 3.02 seconds

User Lkostka
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