199k views
3 votes
If
\alpha = 65° and j = 11 mm, what is the value of h to the nearest tenth of a millimeter?

A. 4.7 mm
B. 12.1 mm
C. 5.1 mm
D. 8.6 mm

If \alpha = 65° and j = 11 mm, what is the value of h to the nearest tenth of a millimeter-example-1

2 Answers

5 votes

Answer:

12.1

Explanation:

User Ionut Negru
by
6.8k points
4 votes

Answer:

C. 5.1 mm

Explanation:

Since this is a right triangle, we can use trig functions

tan alpha = opposite/ adjacent

tan alpha = j/h

tan 65 = 11/h

Multiply both sides by h

h tan 65 = 11/h *h

h tan 65 = 11

Divide each side by tan 65

h tan 65 / tan 65 = 11 / tan 65

h = 11 / tan 65

h =5.12938424

To the nearest tenth

h = 5.1

User Richardsun
by
7.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.