Answer:
(2, 2), (3, 1), (4, 2)
Explanation:
y ≥-1/3 x + 2
y < 2x + 3
(2, 2), (3, 1), (4, 2)
(2, 2), (3, –1), (4, 1)
(2, 2), (1, –2), (0, 2)
(2, 2), (1, 2), (2, 0)
I will assume which we determining which set of points is a solution
(2,2) is in all the sets, so we ignore it
Looking at the graph, we do not have negative solutions for y when x >0 so (3,-1) cannot be a solution and (1,-2) cannot be a solution
(2, 2), (3, 1), (4, 2)
(2, 2), (3, –1), (4, 1) x
(2, 2), (1, –2), (0, 2) x
(2, 2), (1, 2), (2, 0)
Again looking at the graph (2,0) is not a solution
(2, 2), (3, 1), (4, 2)
(2, 2), (3, –1), (4, 1) x
(2, 2), (1, –2), (0, 2) x
(2, 2), (1, 2), (2, 0) x