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9 votes
How much heat is transferred when 494 g of iron cool from 73.9 °C to 17.4 °C if the specific heat of iron is 0.9025 J/g*K?

Round your answer to a whole number and include the charge. Do not include units.

User Ben Parsons
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1 Answer

18 votes
18 votes

Answer:

25,190

Step-by-step explanation:

To find the heat transferred, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g·K)

-----> ΔT = change in temperature (K)

Since the specific heat has been given in terms of Kelvin (K), you technically need to convert the temperatures from Celsius to Kelvin (although your ΔT will still be the same). After doing so, you can plug the given values into the equation and solve.

73.9 °C + 273.15 = 347.05 K

17.4 °C + 273.15 = 290.55 K

Q = ? J c = 0.9025 J/g·K

m = 494 g ΔT = 347.05 K - 290.55 K = 56.5 K

Q = mcΔT

Q = (494 g)(0.9025 J/g·K)(56.5 K)

Q = 25,189.6775

Q = 25,190 J

User Yacoby
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3.2k points