Question

At a certain point in space an electron, which has a mass of (9.1x10^-31) Kg, experiences a force of (3.2 x10^-19) Newtons in the +X direction. What is the electric field at this point?

Answer 1

Electric field, E = 2 N/C

Step-by-step explanation:

It is given that,

Mass of an electron,
`m=9.1* 10^(-31)\ kg`

Electric force,
`F=3.2* 10^(-19)\ N` (in +x direction)

We have to find the electric field at this point. The electric field is given by the electric force acting on a charged particle per unit electric charge. Mathematically, it is given by :

`E=(F)/(q)`

q = charge on an electron,
`1.6* 10^(-19)\ C`

`E=(3.2* 10^(-19)\ N)/(1.6* 10^(-19)\ C)`

E = 2 N/C

The electric field at this point is 2 N/C.