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38 votes
63 1/4 - 2 1/5 show your work please

User Jlalcazar
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2 Answers

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22 votes


\\ \rm\Rrightarrow 63(1)/(4)-2(1)/(5)


\\ \rm\Rrightarrow (253)/(4)-(11)/(5)


\\ \rm\Rrightarrow (1221)/(20)


\\ \rm\Rrightarrow61 (1)/(20)

User Deepak Joshi
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2.7k points
22 votes
22 votes

Answer:


\sf 61(1)/(20)

Explanation:

Given expression:


\sf 63 (1)/(4)-2 (1)/(5)

Partition the mixed numbers into fractions and whole numbers, and then subtract them separately.

Subtract the whole numbers:


\implies \sf 63-2=61

Subtract the fractions by changing both fractions into equivalent fractions so both fractions have the same denominator:


\implies \sf (1)/(4)-(1)/(5)


\implies \sf (1 * 5)/(4 * 5)-(1 * 4)/(5 * 4)


\implies \sf (5)/(20)-(4)/(20)

Subtract the numerator:


\implies \sf (5)/(20)-(4)/(20)=(1)/(20)

Put the two answers from the whole numbers and fractions back together:


\implies \sf 61+(1)/(20)=61(1)/(20)

Therefore:


\implies \sf 63 (1)/(4)-2 (1)/(5)=61(1)/(20)

User Mimming
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