Question

The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is its greatest possible value for width?

Answer 1

L= 3w

Perimeter form = 2(l+w)

2(3w + w) = 112

6w + 2w = 112
8w = 112

w= 14

The greatest possible value for w is 14

Hope this helps!

Answer 2

width = 14 , length = 42

Explanation:

Here we have to find the width of the rectangle using the fact that length is 3 times the width and perimeter is given

Let the length of the rectangle = x

Hence the width of the rectangle = 3 x

The formula for the perimeter is

P=2(l+b)

Given P = 112

Hence

112=2(l+b)

l+b=56

substituting values of l and b in this

x+3x= 56

4x=56

x=14

Hence width = 14 cms

length = 3*14 = 42 cms