Question

What is the measure of DF?

Answer 1

BC= DF

B(0,2) , C(3,2)

d= (3-0)^2 + (2-2)^2
d= 9
Square root 9= 3

DF = 3
Hope this helps!

Answer 2

The correct answer is second option

3.2

Explanation:

It is given that, Coordinates of triangle ABC,

A(0, 1), B(0, 2) and C(3, 2)

ΔABC ≅ ΔDEF

Therefore we can write, AB = DE, BC = EF and AC = DF

To find the measure of DF

DF = AC

(0, 1) C(3, 2)

By using distance formula,

AC = √[(3 - 0)² + ( (2 - 1)²]

= √(9 + 1) = 3.16≈ 3.2