Question

One number is 4 less than 3 times a second number. If 3 more than two times the first number is decreased by 2 times the second number, the result is 11. Use the substitution method. What is the first number?

Answer 1

The first number is 8

Explanation:

Let

x -----> the first number

y ----> the second number

x=3y-4 ----> equation A

3+2x-2y=11 ----> equation B

Substitute equation A in equation B and solve for y

3+2(3y-4)-2y=11

3+6y-8-2y=11

4y=11+5

y=16/4=4

Find the value of x

x=3(4)-4=8