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If nP3 /nC2 = 6, find the value of n


User Uhall
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1 Answer

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(_nP_3)/(_nC_2)=6\\\\((n!)/((n-3)!))/((n!)/(2!(n-2)!))=6\\\\(n!)/((n-3)!)\cdot (2(n-2)!)/(n!)=6\\\\2(n-2)=6\\\\2n-4=6\\\\2n=10\\\\n=5

User Kremerd
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