Answer: The correct answer is Option B.
Step-by-step explanation:
To calculate the number of moles, we use the equation:
....(1)
- For
:
Given mass of nitrogen gas = 10 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in above equation, we get:

The given chemical reaction follows:

As, oxygen gas is present in excess. Thus, it is considered as an excess reagent and nitrogen is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
1 mole of nitrogen gas produces 2 moles of nitrogen oxide.
So, 0.357 moles of nitrogen gas will produce =
of nitrogen oxide.
Now, calculating mass of nitrogen oxide by putting values in equation 1, we get:
Moles of nitrogen oxide = 0.714 mol
Molar mass of nitrogen oxide = 30 g/mol
Putting values in equation 1, we get:

Hence, the correct answer is Option B.