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How many moles of gas are present if p=11 atm, V=12L, T=185k?​

User Coturiv
by
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1 Answer

1 vote

Answer:

8.69 mol.

Step-by-step explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 11.0 atm).

V is the volume of the gas in L (V = 12.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 185.0 K).

∴ n = PV/RT = (11.0 atm)(12.0 L)/(0.0821 L.atm/mol.K)(185.0 K) = 8.69 mol.

User Bryce Drew
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