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At 450 mm Hg a gas has a volume of 760 L, what is its volume at standard pressure​

User Pleonasmik
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Answer:

450.0 L.

Step-by-step explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂).

V₁ = 760.0 L, P₁ = 450.0 mm Hg,

V₂ = ??? L, ​P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).

∴ V₂ = (P₁V₁)/(P₂) = (760.0 L)(450.0 mm Hg)/(760.0 mm Hg) = 450.0 L.

User Sod
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