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Use natural logarithms to solve the equation 5e^3x+7=21​

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Answer:

5e^(3x+7)=21

e^(3x+7)=4.2

(3x+7)lne=ln4.2

lne=1

3x+7=1.435

3x= -5.565

x= -1.855

User Armin Torkashvand
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