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What is the area of the irregular polygon shown below?

What is the area of the irregular polygon shown below?-example-1
User Akatum
by
5.7k points

2 Answers

1 vote

Answer:

D. 49 sq. units

Explanation:

Find the area of the triangle up top first then multiply it by 4 to get the area of the rhombus up top:

4 x 3 = 12

12/2 = 6

6 x 4 = 24

now solve the lower square:

5 x 5 = 25

now add the two together:

25 + 24 = 49

User Ftagliacarne
by
5.3k points
5 votes

Answer:

Correct option is:

D. 49 sq. units

Explanation:

The irregular polygon shown is the combination of rhombus and square

The lower part of the polygon is square with side 5 units

and the upper part of the polygon with rhombus with diagonal (4+4)=8 and (3+3)=6 units

Area of irregular polygon=Area of square+Area of rhombus

= side²+Product of diagonals/2

= 5²+(8×6)/2 sq. units

= (25+24) sq. units

= 49 sq. units

Hence, Correct option is:

D. 49 sq. units

User Craigds
by
5.2k points
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