Question

A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106 meters/second, what is the force acting on the electrons? The value of q = -1.6 × 10-19 coulombs.

Answer 1

`4.7\cdot 10^(-14)N`

Step-by-step explanation:

For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:

`F=qvB`

where

q is the magnitude of the charge

v is the velocity

B is the magnetic field strength

In this problem,

`q=1.6\cdot 10^(-19) C`

`v=6.5\cdot 10^6 m/s`

`B=4.5\cdot 10^(-2) T`

So the force experienced by the electrons is

`F=(1.6\cdot 10^(-19)C)(6.5\cdot 10^6 m/s)(4.5\cdot 10^(-2) T)=4.7\cdot 10^(-14)N`